Section 2.6 Homework Answer

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Section 2.6 Homework

1.   Consider the following equation. 

5x2y2=3

(a) Find y’  by implicit differentiation.

(b) Solve the equation explicitly for y and differentiate to get y’  in terms of x.

 

2. Find dy/dx  by implicit differentiation.

x24xy+y2=4

 

3.  Find dy/dx  by implicit differentiation.

x2x+y=y2+5

 

4. Find dy/dx  by implicit differentiation.

y cos (x) =2x2+5y2

 

5.  Find dy/dx  by implicit differentiation.

cos(xy)=1+sin(y)

 

6. Find dy/dx  by implicit differentiation.

7xy=6+x2y

 

7   Find dy/dx  by implicit differentiation.

x sin(y)+y sin(x) =4

 

8   Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy.

x5y2x5y+5xy3=0

 

9.  Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy.

y sec(x) = 6x tan(y)

 

10.  Use implicit differentiation to find an equation of the tangent line to the curve at the given point.

 

11.  Find y” by implicit differentiation.

x2+2y2=2

 

12. If 

x2+xy +y3=1

find the value of y”’  at the point where x = 1.

 

 

 

 

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Section 2.6 Homework Answers

12. If 

x2+xy +y3=1

find the value of y”’  at the point where x = 1.

 

Answer: y”’= 42

This question is taken from Math 261 – Calculus I » Spring 2022 » Homeworks